(A) In positron emission,a proton $(p)$ is converted into a neutron $(n)$ and a positron $(e^+)$ is emitted: $p \rightarrow n + e^+$. Since the total

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(A) In positron emission,a proton $(p)$ is converted into a neutron $(n)$ and a positron $(e^+)$ is emitted: $p \rightarrow n + e^+$. Since the total number of nucleons (protons + neutrons) remains constant during this process,the mass number $(A)$ of the resulting isotope remains the same. Therefore,the correct option is $(A)$.

Class 12 Chemistry Nuclear Chemistry Nucleus (Stability and Reaction)

Medium

Positron emission results from the transformation of one nuclear proton into a neutron. The isotope thus produced possesses

A
Same mass number
B
Higher nuclear charge
C
Intense radioactivity
D
No radioactivity

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Nucleus (Stability and Reaction)

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Positron emission results from the transformation of one nuclear proton into a neutron. The isotope thus produced possesses

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